No matter how you look at it electricity will travel this way. you could have 10 feet of wire between the bulb and the switch, but wire resistence is negligable. it has no effect to the high amounts of resistence the bulb would have before energizing.
This is assuming that the resistence stated in the diagram is a light bulb!
damn. 78 and I work on mechanical equipment for a living. that's sad.
I made it to question 10 and said fuck this!!!
1/R(resultant) = 1/R(switch leg)+1/R(light leg)
When the switch is closed the majority of current should flow through the switch leg (assuming small resistance in the wire and switch), but current will still flow through the light leg as well. The light won't be as bright as the others, but it will be lit.
Doesn't the bulb lighting to any degree depend on amperage? If there isn't enough, it won't light?
The drawing doesn't specify, so how do you know there is enough to light the bulb? I think this test question is correct for all intents and purposes, unless they include these other values.
Crap, guess I know which side I fall on.
96. only because i confused the battery answers. series = multiply voltage.
I must be stupid, only 92%. Maybe I should read the questions a little slower.
I should of went with my gut. I new the right answer to maybe 60% of the questions I Fudged, I just thought about it too much.